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Assembly Language for x86 Processors (6th Edition) http://goo.gl/n3ApG
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Rasim from Rasmurtech.com give us another tutorial on Assembly Language Programming . In this tutorial Rasim talks about how to copy smaller values to larger ones. Example: (mov ax, cl) won’t work because “ax” is a 16-bit register and “cl” is a 8-bit register, but Rasim show us a way around it.
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3.1 If-Then-Else
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Mr. Muratovic took the time to create a crash course for everyone that needs a quick hands-on application and yet he gets so many complaints. I’m assuming he has a certain time limit for each lesson but at least he’s touching on a lot of different methods and implementations that can be helpful. Don’t watch it, if it bothers you that much or simply read the book.
It seems to me that really all you are doing is moving an 8-bit value into an 8-bit register. Not actually moving an 8-bit value into 16-bit register AX. Yes, you are zeroing out AX but not actually moving var1 to AX. Since var1 is 8-bit and AL is an 8-bit register then there should’nt be any issue making this move in the first place. How do you actually move 8-bit var1 into 16-bit regester AX with only using MOV, not MOVZX or MOVSX?
Hi,
im having trouble with div because i need for the user to input both numbers and just show the answer the problem is, the register that receives the number is AL, how will i move the value of AL to AX?
¿Como puedo pasar un valor de ax a bx, utilizando ciclos, copiado bit por ciclo, partiendo por el menos significativo.?
espero me puedas responder.
gracias
Why complicating things when you have MOVSX & MOVZX instructions?
You should explain each tutorial in detail not just reading it, beginners find it very hard to catch up but thank you for your effort.
thank you
another example of this:
var1 dw 1234h
start:
xor ax,ax
mov al,byte [var1] ;copy 34h to al
mov ah,byte [var1+1] ;copy 12h to ah
Where are you from?