#include
#include
#include
#include
#include

int main()
{

int a;
int howMany;
int maxamount = 10;

printf(“how many times as you want loop to loop? (up to 10) “);
scanf(” &d”, &howMany);

for(a=1; a<=maxamount; a++){ printf("%dn", a); if(a==howMany){ break; } } return 0; } it dosent wooooork!! help please

Have fun with this little piece of code guys:

#include “stdio.h”
#include “stdlib.h”
#include “ctype.h”
#include “string.h”
#include “math.h”

int main()
{

int number, guess, i;

number = 21;
i = 0;

printf(“%sn”, “Hello, I’m thinking of a number, you’re gonna guess it in three tries!”);

while(i++ < 3) { printf("%s %d: ", "Try number", i); scanf("%d", &guess); if (guess > number)
{
printf(“%sn”, “It’s lower than that! Try again!”);
} else if (guess < number) { printf("%sn", "It's higher than that! Try again!"); } else { printf("%s %d %s!n", "Great job! You guessed it in ", i, (i == 1) ? "try" : "tries"); break; } } printf("%sn", "Oops! Game over!"); return 0; }

how come you don’t need an ampersand right before the a? he did it for howmany, but not a and I don’t get why not.

so if i want an error check, maybe like if they put something greater than 10, can i make an if statement saying
if (howmany>10) {printf(“please input number between 0 and 1”);}

Why don’t we just use this way ? : 
int main()
{
  int a,i;
  printf(“How many loops?: “);
  scanf(“%d”,&a);
  for(i=0;i<=a;i++){     printf("%d",i);   } }

can i also do this?

int main ()
{

int a;
int z;

printf(“your number: “);
scanf(“%d”,&z);

for (a=1;a<=z;a++) { printf("%d",a); } return 0; }

Im confused… I input this code and it did not break (aside from that my code wouldnt even run if didn’t take off maxAmount and manually input 10). Can someone please tell me what I did wrong?

#include
#include
#include

LOL i put max to 1 million and wrote loop 999999 times…….
It took 88 seconds

Good one but still this doesn’t show how many you can loop, its basically loop until the number

For some reason, my code doesn’t work. I’m pretty sure it’s correct: 
#include
#include
#include
#include
#include

int main()
{
    int a;
    int howMany;
    int maxAmount = 10;

    printf(“How many rows do you want to print? (up to 10) “);
    scanf(” %d”, &howMany);

    for(a=1; a<=howMany; a++){         printf("%dn", a);         if(a==maxAmount){             break;         }     }     return 0; }

Why can’t I initialize a variable inside of the forloop like > for(int i = 0; i < 5; i++) {} .... It was possible in CS50 ide so I am quite confused atm, does it depend on the ide or what?

It doesn’t break if I enter 10+ value. :/

Here is code I written:

#include
#include
#include
#include
#include

int main()
{
   int number;
   int howMany;
   int maxAmount = 10;

   printf(“How many times you want loop to loop? (Up to 10) n”);
   scanf(” %d”, &howMany);

   for(number=1; maxAmount<=10; number++){         printf("%dn", number);     if(number==howMany){         break;     }    }    return 0; } What's Wrong? :/

Why doesnt it work ?

#include
#include
#include
#include
#include

int main()
{
int a;
int b;

printf(“Press p many times!!!n”);

while(b>100) {
scanf(“%s”,a);

if(a==’p’) {
b++;
} else{
printf(“Youve lost the game.”);
break;
}
}

return 0;
}

First